0=3(3x)^2+7

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Solution for 0=3(3x)^2+7 equation: 



0=3(3x)^2+7

We move all terms to the left:

0-(3(3x)^2+7)=0

We add all the numbers together, and all the variables

-(33x^2+7)=0

We get rid of parentheses

-33x^2-7=0

a = -33; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·(-33)·(-7)
Δ = -924
Delta is less than zero, so there is no solution for the equation

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